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MATH QUESTION

Posted: Thu Aug 30, 2007 4:18 pm
by cawck mongler
So whoever gets this right is the new king of the forums or something.

t^3+t^2-3t-9
---------------
t+3

Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.

The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.

Re: MATH QUESTION

Posted: Thu Aug 30, 2007 4:31 pm
by diddle
cawck mongler wrote:So whoever gets this right is the new king of the forums or something.

t^3+t^2-3t-9
---------------
t+3

Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.

The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.


=7

Posted: Thu Aug 30, 2007 4:32 pm
by Arbustos
Disregard ^

The answer is t^2+2t-3

So am I the king of the forums or something?

Posted: Thu Aug 30, 2007 4:34 pm
by Norse
t = -1, -1.44 or 1.44

Posted: Thu Aug 30, 2007 4:35 pm
by Norse
The above results are when the subsequent graph line pass through the t-axis...(well, not quite the t-axis, but at y=6)

:D

Posted: Thu Aug 30, 2007 4:36 pm
by Arbustos
Why are you people giving values? The answer is a factor.

Posted: Thu Aug 30, 2007 4:37 pm
by Arbustos
Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

:D


You solved for t... you didn't give the answer :?

Posted: Thu Aug 30, 2007 4:38 pm
by Arbustos
BTW I hate math. This is just coming back from 9th grade :wink:

Posted: Thu Aug 30, 2007 4:39 pm
by Norse
Arbustos wrote:
Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

:D


You solved for t... you didn't give the answer :?


yes I did, did you want me to give a basic factorized equation? or prefer me to give the actual value?

Posted: Thu Aug 30, 2007 4:41 pm
by Aegnor
t=3
, it can't be -3 because you get division by zero then.

Posted: Thu Aug 30, 2007 4:42 pm
by Arbustos
Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

Posted: Thu Aug 30, 2007 4:42 pm
by Norse
t^3+t^2-3t-9=0

(t^2-3)(t+1)-6=0

(t-3^0.5)(t-3^0.5)(t+1)-6=0

solved

Posted: Thu Aug 30, 2007 4:42 pm
by Arbustos
Screw this, I hate math :evil:

Posted: Thu Aug 30, 2007 4:43 pm
by Norse
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?


It isnt a parabola, it becomes muted 3 times, like all cubed equations

Posted: Thu Aug 30, 2007 4:44 pm
by Arbustos
Norse wrote:
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?


It isnt a parabola, it passes the t-axis 3 times, like all cubed equations


No, I mean the factor. Explain this to me, I've forgotten so much :oops:
Did you divide by the t+3?

Posted: Thu Aug 30, 2007 4:45 pm
by Aegnor
(t+3)(t+3)(t-3)
----------------- = 0
t+3


Do your own math from here buddies :)


I simplified the original equation. Now you can eliminate the denominator, and you get:

(t+3)(t-3)=0

Magical isn't it?

Posted: Thu Aug 30, 2007 4:46 pm
by Norse
Arbustos wrote:
Norse wrote:
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?


It isnt a parabola, it passes the t-axis 3 times, like all cubed equations


No, I mean the factor. Explain this to me, I've forgotten so much :oops:
Did you divide by the t+3?


no no, just factorized the original equation.

Posted: Thu Aug 30, 2007 4:47 pm
by Arbustos
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3


Do your own math from here buddies :)


@$#% That was too easy... I don't have a mind for math :(

Posted: Thu Aug 30, 2007 4:48 pm
by Norse
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3


Do your own math from here buddies :)


wrong im afraid...

expand them factors, and yyou will end up with..

t^3+6t^2+18t-27

a little off there

Posted: Thu Aug 30, 2007 4:49 pm
by Norse
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3


Do your own math from here buddies :)


I simplified the original equation. Now you can eliminate the denominator, and you get:

(t+3)(t-3)=0

Magical isn't it?


hehe, way off the mark there, nothings ever that easy....go back and re-read

Posted: Thu Aug 30, 2007 4:49 pm
by Arbustos
Norse wrote:
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3


Do your own math from here buddies :)


wrong im afraid...

expand them factors, and yyou will end up with..

t^3+6t^2+18t-27

a little off there


Well, I blindly accepted it because the steps were correct. Damn this :|

Posted: Thu Aug 30, 2007 4:51 pm
by Norse
(t+3)(t+3) = t^2+9t+9

{t^2+9t+9}(t-3) =t^3+6t^2+18t-27

Posted: Thu Aug 30, 2007 4:52 pm
by Aegnor
Ah crap, I guess you're right! I feel into that trap blindly :)

Posted: Thu Aug 30, 2007 4:54 pm
by Arbustos
From the factors, wouldn't the solution be 1, since -3 causes a division by zero scenario?

Factors: (t+3)(t+3)(t-1)

Posted: Thu Aug 30, 2007 4:56 pm
by Norse
Norse wrote:t^3+t^2-3t-9=0

(t^2-3)(t+1)-6=0

(t-3^0.5)(t-3^0.5)(t+1)-6=0

solved


QFT! :lol:

^0.5 means squared root, btw.