Post Your Dice Streaks Here

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CHEWKY
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Re: Post Your Dice Streaks Here

Post by CHEWKY »

The Dice just plain suck in all conquer club games! I have NEVER EVER seen such horrible consecutive BAD ROLLS game to game! I have lost consistently when I have had a 4-1 or 3-1 roll, not to mention the pathetic 50/50 roll when it is 6-3 or 7-4 in my favor. I have also noticed that on avaerage game to game it takes getting 5 cards to cash in 80% of the time. I have also noticed going first in games is nearly 15% chance. SICK, PATHETIC, and really not worth it any more.

Yet, it appears that high rankers get special favor? It appears that way in every game against them, they go first, have advantage auto positioning and flawless dice! So ............. What goes on behind the scene at conquer club? Question: are cc employees involved in games? Are there special codes to give favor/ advantage to specific accounts on this site?
Something sure smells fishy and I know many users with this very complaint.

I for one, will NOT renew my membership and will NOT recommend this site to anyone that matters.

enjoy one of the biggest time wasters a human life can get involved with!
I leave you all with a gift in my chef hat .... better hold your noses! p u

:lol:
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Commander62890
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Re: Post Your Dice Streaks Here

Post by Commander62890 »

Does it occur to you that everyone starts out at 1000? How can high-rankers become high-rankers if they are getting perpetually shitty dice when they are low-rankers?




I love your wall, Chewky. Very entertaining stuff.
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natty dread
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Re: Post Your Dice Streaks Here

Post by natty dread »

CHEWKY wrote:ARGHLEBLARGH


:shock:

Worst dice complaint ever.
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RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

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Lets see the penultimate line, shall we?

4-4-6-6-4-5-5-6-6-4-5-5-6 = what´s this? 1,2 and 3 were in the bahamas and got sucked by the bermuda triangle? 13 rolls and not a single result below 4?

this is EXACTLY THE SAME of flipping a coin thirteen bloody times and have it land tails EVERY SINGLE OF THEM.

Go ahead, try...odds are more or less one-in-ten-thousand you will get one.


EDIT>

Image

Line six = six TWO in a row, odds= 1 in 50.000

both those happenings are in my 2.262 rolls batch - and I bet I can fish in there more 1-in-more-than-10.000 anomalies.
RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

THIS IS SERIOUSLY FUCKED UP

I tried to kill a premium member, and lost 33 armies to kill 13

Then I went to check the rolls

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what a SURPRISE... lets see the bottom line....

6-6-4-5-4-6-5-5-5-6-4-4 = AGAIN we have 12 rolls, and not a single one below 4

so, in 3 lines (about 70 rolls) from the dice streak analiser, we can see 13 rolls where there are no 1,2 or 3's and then, once again, 12 rolls without 1´s 2´s or 3´s

In 70 rolls we got TWO one-in-10.000 happenings.

get 12 dice, roll them until you get NO ones NO twos and NO threes on ANY of them.

then do it again, in less than 5 tries (12x5=60, the interval between one and the other)

you wont manage to do it within a lifetime

On a second note, on the top line of the screenshot we have 1-1-1-1-3-5-5-5-5-1-5-1-1 another 12 streak with, this time, with almost only TWO numbers.
barrycarter
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Re: Post Your Dice Streaks Here

Post by barrycarter »

http://gaygamer.net/images/l2_46730.jpg

I get a 403 (authorization denied) error when accessing this.

The chance of losing 967 to 1 is 5.745487928449193*10^-355, which suggests that the dice may be misprogrammed.

I'm assuming ConquerClub's source code is not open?
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hairy potter
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Re: Post Your Dice Streaks Here

Post by hairy potter »

i was playing a moderator and i had 100 and they had 2 and i lost and it was my 1 versus their 2 and i lost the game
barrycarter
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Re: Post Your Dice Streaks Here

Post by barrycarter »

hairy potter wrote:i was playing a moderator and i had 100 and they had 2 and i lost and it was my 1 versus their 2 and i lost the game


Probability of that happening is 1.18571*10^-26

What game number was it?
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hairy potter
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Re: Post Your Dice Streaks Here

Post by hairy potter »

barrycarter wrote:Probability of that happening is 1.18571*10^-26


well then there is a probability

don't forget to take into account that the odds are stacked in the defender's favour.
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Re: Post Your Dice Streaks Here

Post by barrycarter »

hairy potter wrote:
barrycarter wrote:Probability of that happening is 1.18571*10^-26


well then there is a probability

don't forget to take into account that the odds are stacked in the defender's favour.


Well, there's ALWAYS a probability. However, ~10^-26 is way too low a probability to occur by chance (at least not consistently). And yes, the calculation takes that into consideration.

My thought: random.org is giving out random numbers, but the auto-assault part of CC's code is somehow misusing or re-using random numbers. If CC would release that code publicly (or to me under an NDA), we could review it.

Looking for patterns in streaks might help too.
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hairy potter
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Re: Post Your Dice Streaks Here

Post by hairy potter »

barrycarter wrote:
hairy potter wrote:
barrycarter wrote:Probability of that happening is 1.18571*10^-26


well then there is a probability

don't forget to take into account that the odds are stacked in the defender's favour.


Well, there's ALWAYS a probability. However, ~10^-26 is way too low a probability to occur by chance (at least not consistently). And yes, the calculation takes that into consideration.

My thought: random.org is giving out random numbers, but the auto-assault part of CC's code is somehow misusing or re-using random numbers. If CC would release that code publicly (or to me under an NDA), we could review it.

Looking for patterns in streaks might help too.


i think the mods mis-use quite a lot of things on here
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grifftron
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Re: Post Your Dice Streaks Here

Post by grifftron »

hairy potter wrote:i was playing a moderator and i had 100 and they had 2 and i lost and it was my 1 versus their 2 and i lost the game


You had 100? then you lost your 1 to their 2? well of course you would lose your 1 to their 2...

anyways i searched threw your massive game count and couldn't spot 1 game with any mod... was it your hairy potter acct?

-griff

edit: chip very cool tool! i wish i woulda found this earlier.. i d/l it and looking forward to seeing my results.. also staying away from masli in games!
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RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

I love to see this evenly-distribuited results

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23 dice rolls = ten sixes, four of them in a row.

I think this time they used 10 sided dice, with faces numbered 1;2;3;4;5;6;6;6;6;6
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niMic
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Re: Post Your Dice Streaks Here

Post by niMic »

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RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

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eight losses in a row. on 3x1 a attack!!!

As usual, you will dismiss this as a common occourence, that every player should expect to get once in a week.
barrycarter
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Re: Post Your Dice Streaks Here

Post by barrycarter »

The odds against that are only ~5563 to 1 against, and, given the number of dice rolls on conquerclub, that's not too impressive.

Losing 100 vs 2 is unlikely enough to be suspicious.
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dyingfetus
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Re: Post Your Dice Streaks Here

Post by dyingfetus »

I once attacked 63 vs. 3.....and lost. i dont want to hear anyone complaine about bad dice....
RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

dyingfetus wrote:I once attacked 63 vs. 3.....and lost. i dont want to hear anyone complaine about bad dice....


Why? Because you want people to have similar results and feel better because of it?

Or because you realize it is broken and dont care?

to lose a 63x3 is almost impossible to happen. It is the same thing as you fire up the LHC and see the end of earth because of the black hole thing.

It can happen, in theory, but it is SO far-fetched to excpect it to actually happen that it should not be expected to be seen in a million years.
RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

That leads to thinking: if the Large Hadron Collider ever uses CC intensity cubes to calculate anything, we should expect the end of life in earth to happen.

Several times a week.
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maasman
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Re: Post Your Dice Streaks Here

Post by maasman »

RADAGA wrote:That leads to thinking: if the Large Hadron Collider ever uses CC intensity cubes to calculate anything, we should expect the end of life in earth to happen.

Several times a week.

If the the LHC did as many trials as CC does cubes, then yes, the earth could be dead several times a week (not taking into account that the LHC is harmless, regardless of the number of trials).
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L M S
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Re: Post Your Dice Streaks Here

Post by L M S »

I have a fairly large sample to post (I think) but the DA keeps freezing up...any suggestions?
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Timminz
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Re: Post Your Dice Streaks Here

Post by Timminz »

L M S wrote:I have a fairly large sample to post (I think) but the DA keeps freezing up...any suggestions?

Wait longer. That used to happen to me too.


Also, it's nice to see that some things never change. RADAGA is still cherry-picking his data to suit his need to whine. Show us your overall data, or STFU, already.
RADAGA
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Re: Post Your Dice Streaks Here

Post by RADAGA »

you shut the f*ck up, ok? I have posted large samples several times. And in my 17.000 dice I have "cherry picked" TENTHS of situations that should happen only on MILLION-sized samples.

When you find something like> win 32 in a row, or lose 17 in a row, you dont need to look at the big picture to know that something is wrong.

lets see, LESS THAN 4.000 ROLLS>

1)there is a 34 win and a 18 loss in a row. lets see the 34 kills in a row: would it be 17 3x2 in double wins in sequence? 0,00000077% - ONE in ONE HUNDRED AND FIFTY MILLION chance

2) the 18 loss would be 9 doulbe losses in a row - 0,0051%

Number of Rolls : 3908


Most Consecutive Troops Defeated: 34
Most Consecutive Troops Lost: 18
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Timminz
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Re: Post Your Dice Streaks Here

Post by Timminz »

RADAGA wrote:shut the f*ck up


Oh, that's what that stands for?

I beg your pardon, good sir.
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Timminz
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Re: Post Your Dice Streaks Here

Post by Timminz »

In probability theory, the birthday problem, or birthday paradox[1] pertains to the probability that in a set of randomly chosen people some pair of them will have the same birthday. By the pigeonhole principle, the probability reaches 100% when the number of people reaches 367 (including February 29 births). But perhaps counter-intuitively, 99% probability is reached with just 57 people, and 50% probability with 23 people. These conclusions are based on the assumption that each day of the year (except February 29) is equally probable for a birthday.


In other words, even if it's something that only happens every 1 in 365 times, you only have to try 23 times before you're most likely to see the same, very unlikely, result twice, and by the time you've tried only 57 times, you've got a 99% chance of having the same result twice.

Do you see the correlationship between this example, and your most recent complaints?
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