MATH QUESTION

cawck mongler · Post by **cawck mongler** » Thu Aug 30, 2007 4:18 pm

So whoever gets this right is the new king of the forums or something.

t^3+t^2-3t-9
---------------
t+3

Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.

The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.

diddle · Post by **diddle** » Thu Aug 30, 2007 4:31 pm

cawck mongler wrote:So whoever gets this right is the new king of the forums or something.

t^3+t^2-3t-9
---------------
t+3

Everynight my dad tells me to do this shit, and everynight he gets pissed off because I don't know how, so tell me. DONT ASK ME WHY I HAVE TO DO THIS.

The t^2 and stuff means 2 over t, and its t^3+t^2 etc. over t+3, so divide.

=7

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:32 pm

Disregard ^

The answer is t^2+2t-3

So am I the king of the forums or something?

Norse · Post by **Norse** » Thu Aug 30, 2007 4:34 pm

t = -1, -1.44 or 1.44

Norse · Post by **Norse** » Thu Aug 30, 2007 4:35 pm

The above results are when the subsequent graph line pass through the t-axis...(well, not quite the t-axis, but at y=6)

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:36 pm

Why are you people giving values? The answer is a factor.

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:37 pm

Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

You solved for t... you didn't give the answer

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:38 pm

BTW I hate math. This is just coming back from 9th grade :wink:

Norse · Post by **Norse** » Thu Aug 30, 2007 4:39 pm

Arbustos wrote:
Norse wrote:The above results are when the subsequent graph line pass through the t-axis...

You solved for t... you didn't give the answer

yes I did, did you want me to give a basic factorized equation? or prefer me to give the actual value?

Aegnor · Post by **Aegnor** » Thu Aug 30, 2007 4:41 pm

t=3
, it can't be -3 because you get division by zero then.

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:42 pm

Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

Norse · Post by **Norse** » Thu Aug 30, 2007 4:42 pm

t^3+t^2-3t-9=0

(t^2-3)(t+1)-6=0

(t-3^0.5)(t-3^0.5)(t+1)-6=0

solved

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:42 pm

Screw this, I hate math :evil:

Norse · Post by **Norse** » Thu Aug 30, 2007 4:43 pm

Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

It isnt a parabola, it becomes muted 3 times, like all cubed equations

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:44 pm

Norse wrote:
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

It isnt a parabola, it passes the t-axis 3 times, like all cubed equations

No, I mean the factor. Explain this to me, I've forgotten so much :oops:

Did you divide by the t+3?

Aegnor · Post by **Aegnor** » Thu Aug 30, 2007 4:45 pm

(t+3)(t+3)(t-3)
----------------- = 0
t+3

Do your own math from here buddies

I simplified the original equation. Now you can eliminate the denominator, and you get:

(t+3)(t-3)=0

Magical isn't it?

Norse · Post by **Norse** » Thu Aug 30, 2007 4:46 pm

Arbustos wrote:
Norse wrote:
Arbustos wrote:Why did you alter your results post 4 times? And I may be forgetting something (and probably am), but how do you get 3 x-values with a parabola?

It isnt a parabola, it passes the t-axis 3 times, like all cubed equations

No, I mean the factor. Explain this to me, I've forgotten so much
Did you divide by the t+3?

no no, just factorized the original equation.

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:47 pm

Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3

Do your own math from here buddies

@$#% That was too easy... I don't have a mind for math

Norse · Post by **Norse** » Thu Aug 30, 2007 4:48 pm

Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3

Do your own math from here buddies

wrong im afraid...

expand them factors, and yyou will end up with..

t^3+6t^2+18t-27

a little off there

Norse · Post by **Norse** » Thu Aug 30, 2007 4:49 pm

Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3

Do your own math from here buddies

I simplified the original equation. Now you can eliminate the denominator, and you get:

(t+3)(t-3)=0

Magical isn't it?

hehe, way off the mark there, nothings ever that easy....go back and re-read

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:49 pm

Norse wrote:
Aegnor wrote:(t+3)(t+3)(t-3)
----------------- = 0
t+3

Do your own math from here buddies

wrong im afraid...

expand them factors, and yyou will end up with..

t^3+6t^2+18t-27

a little off there

Well, I blindly accepted it because the steps were correct. Damn this

Norse · Post by **Norse** » Thu Aug 30, 2007 4:51 pm

(t+3)(t+3) = t^2+9t+9

{t^2+9t+9}(t-3) =t^3+6t^2+18t-27

Aegnor · Post by **Aegnor** » Thu Aug 30, 2007 4:52 pm

Ah crap, I guess you're right! I feel into that trap blindly

Arbustos · Post by **Arbustos** » Thu Aug 30, 2007 4:54 pm

From the factors, wouldn't the solution be 1, since -3 causes a division by zero scenario?

Factors: (t+3)(t+3)(t-1)

Norse · Post by **Norse** » Thu Aug 30, 2007 4:56 pm

Norse wrote:t^3+t^2-3t-9=0

(t^2-3)(t+1)-6=0

(t-3^0.5)(t-3^0.5)(t+1)-6=0

solved

QFT!

^0.5 means squared root, btw.

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